4. 计算:
灵活利用乘法的运算律简化计算.
(1) $(-\dfrac{8}{25})×1.25×(-8)$;
(2) $(-10)×(-8.24)×(-0.1)$;
(3) $(\dfrac{7}{9}-\dfrac{5}{6}+\dfrac{3}{4}-\dfrac{7}{18})×36$;
(4) $-\dfrac{3}{4}×(8-1\dfrac{1}{3}-0.04)$.
灵活利用乘法的运算律简化计算.
(1) $(-\dfrac{8}{25})×1.25×(-8)$;
(2) $(-10)×(-8.24)×(-0.1)$;
(3) $(\dfrac{7}{9}-\dfrac{5}{6}+\dfrac{3}{4}-\dfrac{7}{18})×36$;
(4) $-\dfrac{3}{4}×(8-1\dfrac{1}{3}-0.04)$.
答案:
5. 计算:
(1) $(-2) × 3 × (-4)$;
(2) $(-6) × (-5) × (-7)$;
任何数与0相乘,都得0.
(3) $(-6) × (-0.25) × \frac{11}{14}$;
(4) $(-17) × (-49) × 0 × 13$.
(1) $(-2) × 3 × (-4)$;
(2) $(-6) × (-5) × (-7)$;
任何数与0相乘,都得0.
(3) $(-6) × (-0.25) × \frac{11}{14}$;
(4) $(-17) × (-49) × 0 × 13$.
答案:
6. 计算:
两数相除,同号得正,异号得负,且商的绝对值等于被除数的绝对值除以除数的绝对值的商.
(1) $16÷(-3)$;
(2) $(-91)÷13$;
(3) $(-56)÷(+14)$;
(4) $\dfrac{4}{5}÷(-1)$;
(5) $(-16)÷(-48)$;
(6) $(-0.25)÷\dfrac{3}{8}$.
两数相除,同号得正,异号得负,且商的绝对值等于被除数的绝对值除以除数的绝对值的商.
(1) $16÷(-3)$;
(2) $(-91)÷13$;
(3) $(-56)÷(+14)$;
(4) $\dfrac{4}{5}÷(-1)$;
(5) $(-16)÷(-48)$;
(6) $(-0.25)÷\dfrac{3}{8}$.
答案:
7. 填空题.
$1×(-5)=$______; $1÷(-5)=$______;
$1+(-5)=$______; $1-(-5)=$______;
$(-1)×(-5)=$______; $(-1)÷(-5)=$______;
$(-1)+(-5)=$______; $(-1)-(-5)=$______.
$1×(-5)=$______; $1÷(-5)=$______;
$1+(-5)=$______; $1-(-5)=$______;
$(-1)×(-5)=$______; $(-1)÷(-5)=$______;
$(-1)+(-5)=$______; $(-1)-(-5)=$______.
答案:
8. 化简:
(1) $\frac{-21}{7}$;
(2) $\frac{3}{-36}$;
(3) $\frac{-54}{-8}$;
(4) $\frac{-6}{-0.3}$。
分子和分母都有负号时,可将负号约去。
(1) $\frac{-21}{7}$;
(2) $\frac{3}{-36}$;
(3) $\frac{-54}{-8}$;
(4) $\frac{-6}{-0.3}$。
分子和分母都有负号时,可将负号约去。
答案:
9. 计算:
(1) $0.1÷(-0.001)÷(-1)$;
(2) $(-\dfrac{3}{4})×(-1\dfrac{1}{2})÷(-2\dfrac{1}{4})$;
(3) $(-7)×(-56)×0÷(-13)$;
(4) $(-9)×(-11)÷3÷(-3)$.
(1) $0.1÷(-0.001)÷(-1)$;
(2) $(-\dfrac{3}{4})×(-1\dfrac{1}{2})÷(-2\dfrac{1}{4})$;
(3) $(-7)×(-56)×0÷(-13)$;
(4) $(-9)×(-11)÷3÷(-3)$.
答案:
10. 计算:
(1) $23×(-5)-(-3)÷\frac{3}{128}$;
(2) $(-7)×(-3)×(-0.5)+(-12)×(-2.6)$;
(3) $(1\frac{3}{4}-\frac{7}{8}-\frac{7}{12})÷(-\frac{7}{8})+(-\frac{7}{8})÷(1\frac{3}{4}-\frac{7}{8}-\frac{7}{12})$;
(4) $-\left|-\frac{2}{3}\right|-\left|-\frac{1}{2}×\frac{2}{3}\right|-\left|\frac{1}{3}-\frac{1}{4}\right|-|-3|$.
先计算绝对值里的式子,再根据“正数的绝对值是它本身,负数的绝对值是它的相反数”去掉绝对值的符号,最后进行计算.
(1) $23×(-5)-(-3)÷\frac{3}{128}$;
(2) $(-7)×(-3)×(-0.5)+(-12)×(-2.6)$;
(3) $(1\frac{3}{4}-\frac{7}{8}-\frac{7}{12})÷(-\frac{7}{8})+(-\frac{7}{8})÷(1\frac{3}{4}-\frac{7}{8}-\frac{7}{12})$;
(4) $-\left|-\frac{2}{3}\right|-\left|-\frac{1}{2}×\frac{2}{3}\right|-\left|\frac{1}{3}-\frac{1}{4}\right|-|-3|$.
先计算绝对值里的式子,再根据“正数的绝对值是它本身,负数的绝对值是它的相反数”去掉绝对值的符号,最后进行计算.
答案: