计算：
(1)$(-3)-(+\frac{1}{3})+5-(-1\frac{1}{3})$；
(2)$(-12)-5+(-14)-(-39)$；
(3)$0.25+(-\frac{1}{8})-\frac{3}{4}-\left|-\frac{7}{8}\right|$；
(4)$\frac{5}{6}+(-2\frac{1}{2})-(-1\frac{1}{6})-(+0.5)$；
(5)$5\frac{3}{4}-(-4\frac{2}{3})-5.75+(-7\frac{2}{3})$；
(6)$\frac{2}{9}-(-1\frac{5}{6})+(-1\frac{2}{9})-\frac{1}{3}$；
(7)$(-301)+125+301+(-75)$；
(8)$(-8)-(-15)+(-9)-(-12)$；
(9)$-\frac{31}{3}-(-\frac{58}{7})+(-\frac{9}{7})-(+\frac{32}{3})$；
(10)$(-4\frac{7}{9})-(-3\frac{1}{6})-(+\frac{2}{9})+(+6\frac{1}{6})$。
(1)$(-3)-(+\frac{1}{3})+5-(-1\frac{1}{3})$；
(2)$(-12)-5+(-14)-(-39)$；
(3)$0.25+(-\frac{1}{8})-\frac{3}{4}-\left|-\frac{7}{8}\right|$；
(4)$\frac{5}{6}+(-2\frac{1}{2})-(-1\frac{1}{6})-(+0.5)$；
(5)$5\frac{3}{4}-(-4\frac{2}{3})-5.75+(-7\frac{2}{3})$；
(6)$\frac{2}{9}-(-1\frac{5}{6})+(-1\frac{2}{9})-\frac{1}{3}$；
(7)$(-301)+125+301+(-75)$；
(8)$(-8)-(-15)+(-9)-(-12)$；
(9)$-\frac{31}{3}-(-\frac{58}{7})+(-\frac{9}{7})-(+\frac{32}{3})$；
(10)$(-4\frac{7}{9})-(-3\frac{1}{6})-(+\frac{2}{9})+(+6\frac{1}{6})$。
答案：解：
(1) 原式$= -3 - \frac{1}{3} + 5 + 1\frac{1}{3} = (-3+5) + (-\frac{1}{3}+1\frac{1}{3}) = 2 + 1 = 3$
(2) 原式$= -12 -5 -14 +39 = -31 +39 = 8$
(3) 原式$= \frac{1}{4} - \frac{1}{8} - \frac{3}{4} - \frac{7}{8} = (\frac{1}{4}-\frac{3}{4}) + (-\frac{1}{8}-\frac{7}{8}) = -\frac{1}{2} -1 = -\frac{3}{2}$
(4) 原式$= \frac{5}{6} -2\frac{1}{2} +1\frac{1}{6} -0.5 = (\frac{5}{6}+1\frac{1}{6}) + (-2\frac{1}{2}-\frac{1}{2}) = 2 -3 = -1$
(5) 原式$= 5\frac{3}{4} +4\frac{2}{3} -5\frac{3}{4} -7\frac{2}{3} = (5\frac{3}{4}-5\frac{3}{4}) + (4\frac{2}{3}-7\frac{2}{3}) = 0 -3 = -3$
(6) 原式$= \frac{2}{9} +1\frac{5}{6} -1\frac{2}{9} -\frac{1}{3} = (\frac{2}{9}-1\frac{2}{9}) + (1\frac{5}{6}-\frac{1}{3}) = -1 + 1\frac{1}{2} = \frac{1}{2}$
(7) 原式$= (-301+301) + (125-75) = 0 +50 = 50$
(8) 原式$= -8 +15 -9 +12 = (-8-9) + (15+12) = -17 +27 = 10$
(9) 原式$= -\frac{31}{3} +\frac{58}{7} -\frac{9}{7} -\frac{32}{3} = (-\frac{31}{3}-\frac{32}{3}) + (\frac{58}{7}-\frac{9}{7}) = -21 +7 = -14$
(10) 原式$= -4\frac{7}{9} +3\frac{1}{6} -\frac{2}{9} +6\frac{1}{6} = (-4\frac{7}{9}-\frac{2}{9}) + (3\frac{1}{6}+6\frac{1}{6}) = -5 +9\frac{1}{3} = 4\frac{1}{3}$
(1) 原式$= -3 - \frac{1}{3} + 5 + 1\frac{1}{3} = (-3+5) + (-\frac{1}{3}+1\frac{1}{3}) = 2 + 1 = 3$
(2) 原式$= -12 -5 -14 +39 = -31 +39 = 8$
(3) 原式$= \frac{1}{4} - \frac{1}{8} - \frac{3}{4} - \frac{7}{8} = (\frac{1}{4}-\frac{3}{4}) + (-\frac{1}{8}-\frac{7}{8}) = -\frac{1}{2} -1 = -\frac{3}{2}$
(4) 原式$= \frac{5}{6} -2\frac{1}{2} +1\frac{1}{6} -0.5 = (\frac{5}{6}+1\frac{1}{6}) + (-2\frac{1}{2}-\frac{1}{2}) = 2 -3 = -1$
(5) 原式$= 5\frac{3}{4} +4\frac{2}{3} -5\frac{3}{4} -7\frac{2}{3} = (5\frac{3}{4}-5\frac{3}{4}) + (4\frac{2}{3}-7\frac{2}{3}) = 0 -3 = -3$
(6) 原式$= \frac{2}{9} +1\frac{5}{6} -1\frac{2}{9} -\frac{1}{3} = (\frac{2}{9}-1\frac{2}{9}) + (1\frac{5}{6}-\frac{1}{3}) = -1 + 1\frac{1}{2} = \frac{1}{2}$
(7) 原式$= (-301+301) + (125-75) = 0 +50 = 50$
(8) 原式$= -8 +15 -9 +12 = (-8-9) + (15+12) = -17 +27 = 10$
(9) 原式$= -\frac{31}{3} +\frac{58}{7} -\frac{9}{7} -\frac{32}{3} = (-\frac{31}{3}-\frac{32}{3}) + (\frac{58}{7}-\frac{9}{7}) = -21 +7 = -14$
(10) 原式$= -4\frac{7}{9} +3\frac{1}{6} -\frac{2}{9} +6\frac{1}{6} = (-4\frac{7}{9}-\frac{2}{9}) + (3\frac{1}{6}+6\frac{1}{6}) = -5 +9\frac{1}{3} = 4\frac{1}{3}$