第64页

信息发布者：
B
A
C
C
$6x^3y^2$
$解:\frac {1}{3x^2}=\frac {1×4y}{3x^2×4y}=\frac{4y}{12x^2y}$
$\frac{5}{12xy}=\frac{5×x}{12xy×x}=\frac{5x}{12x^2y}$
$解:\frac {b^2}{6a}=\frac {b^2×2b}{6a×2b}=\frac{2b^3}{12ab}$
$\frac{ac}{4b}=\frac{ac×3a}{4b×3a}=\frac{3a^2c}{12ab}$
$解:\frac {x}{x+2}=\frac {x×(x-2)}{(x+2)×(x-2)}=\frac{x(x-2)}{(x+2)(x-2)}$
$\frac {4x}{x^2-4}=\frac{4x}{(x+2)(x-2)}$
$\frac {2}{2-x}=-\frac {2×(x+2)}{(x-2)×(x+2)}=\frac{-2(x+2)}{(x+2)(x-2)}$
$解:\frac {1}{m^2-9}=\frac {1×2}{(m^2-9)×2}=\frac{2}{2(m+3)(m-3)}\ $
$\frac {1}{2m+6}=\frac {1×(m-3)}{(2m+6)×(m-3)}=\frac{m-3}{2(m+3)(m-3)}\ $

$解:\frac {1}{x^2-x}=\frac {1×(x-1)}{(x^2-x)×(x-1)}=\frac{x-1}{x(x-1)^2}$
$\frac {-1}{x^2-2x+1}=\frac {-1×x}{(x^2-2x+1)×x}=\frac {-x}{x(x-1)^2}$
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