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信息发布者:
$\frac {2023}{2024}$
5
B
M>P>N
a<1且a≠-1
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$解:∵\frac{1}{x}+\frac{1}{y+z}=\frac{1}{2},$
$∴\frac{x+y+z}{x(y+z)}=\frac{1}{2}.\ $
$∴\frac{x(y+z)}{x+y+z}=2.$
$∴\frac {xy+xz}{x+y+z}=2.\ $
$同理\frac {yz+yx}{x+y+z}=3,$
$\frac{zx+zy}{x+y+z}=4.\ $
$∴\frac{xy+xz+yz}{x+y+z}=\frac{9}{2}.\ $
$∴\frac{yz}{x+y+z}=\frac{5}{2},$
$\frac {xz}{x+y+z}=\frac{3}{2},$
$\frac{xy}{x+y+z}=\frac{1}{2}.\ $
$∴\frac{yz}{x+y+z}·\frac {x+y+z}{xz}=\frac{5}{3},$
$∴ \frac {y}{x}=\frac{5}{3} .$
$同理可得\frac{z}{x}=5,\frac{z}{y}=3,$
$∴5x=3y,z=3y.\ $
$∴z=5x,y=\frac{5}{3} x,$
$代人\frac{1}{x}+\frac{1}{y+x}=\frac{1}{2},$
$得\frac{1}{x}+\frac{1}{\frac {20}{3}x}=\frac{1}{2},$
$解得 x=\frac{23}{10}.\ $
$∴\frac{2}{x}+\frac{3}{y}+\frac{4}{z}=\frac{23}{5x}=2.\ $