解:(1)物体重$G = mg = 20\ kg\times10\ N/kg = 200\ N,$有用功$W_{有用}=Gh = 200\ N\times2\ m = 400\ J$
(2)绳子末端移动距离$s = 2h = 2\times2\ m = 4\ m。$拉力做的总功$W_{总}=Fs = 125\ N\times4\ m = 500\ J$
(3)动滑轮的机械效率$\eta=\frac{W_{有用}}{W_{总}}\times100\%=\frac{400\ J}{500\ J}\times100\% = 80\%$