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A
B
$3a^{2}b - 10ab^{2}$
$x-\frac{8}{3}$
$y^{2}-xy + 3$
$10x + 4$
解:
$\begin{aligned}M - 2N&=(3b^{2}+2ab - 4)-2(-8 + 3ab+3b^{2})\\&=3b^{2}+2ab - 4 + 16-6ab - 6b^{2}\\&=(3b^{2}-6b^{2})+(2ab-6ab)+(- 4 + 16)\\&=-3b^{2}-4ab + 12\end{aligned}$
解:
$\begin{aligned}3N-\frac{2}{3}M&=3(-8 + 3ab+3b^{2})-\frac{2}{3}(3b^{2}+2ab - 4)\\&=-24 + 9ab+9b^{2}-2b^{2}-\frac{4}{3}ab+\frac{8}{3}\\&=(9b^{2}-2b^{2})+(9ab-\frac{4}{3}ab)+(-24+\frac{8}{3})\\&=7b^{2}+\frac{23}{3}ab-\frac{64}{3}\end{aligned}$
解:原式​$=(15a^2b - 5ab^2)-(-4ab^2+12a^2b)-2a^2b $​
​$= 15a^2b-5ab^2+4ab^2-12a^2b - 2a^2b$​
​$=a^2b - ab^2.$​
​$ $​当​$a =-\frac {1}{2},$​​$b = 2$​时,
​$ $​原式​$=(-\frac {1}{2})^2×2-(-\frac {1}{2})×2^2=\frac {1}{4}×2+\frac {1}{2}×4=\frac {1}{2}+2=\frac {5}{2}$​