解:
$\begin{aligned}&-1\frac{7}{8}+(-4\frac{1}{4})+(+2\frac{1}{2})-(+3\frac{1}{8})\\=&-\frac{15}{8}-\frac{17}{4}+\frac{5}{2}-\frac{25}{8}\\=&(-\frac{15}{8}-\frac{25}{8})-\frac{17}{4}+\frac{5}{2}\\=&-\frac{40}{8}-\frac{17}{4}+\frac{10}{4}\\=& - 5-\frac{7}{4}\\=&-\frac{20}{4}-\frac{7}{4}\\=&-\frac{27}{4}\end{aligned}$