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信息发布者:
方程$2x^2 + 2x + \frac{1}{2} = 0$有解,$x_1 = x_2 = -\frac{1}{2}.$方程$2x^2 - x + 1 = 0$没有实数解.
用配方法解一元二次方程的一般步骤

(1)$x_1 = \frac{4 + \sqrt{14}}{2}$或$x_2 = \frac{4 - \sqrt{14}}{2}$ 
(2)$x_1 = -2 + \sqrt{6}$或$x_2 = -2 - \sqrt{6}$ 
(3)$x_1 = 0$或$x_2 = -\frac{3}{2}$
(4)$x_1 = \frac{3 + 2\sqrt{3}}{3}$或$x_2 = \frac{3 - 2\sqrt{3}}{3}$ 
(5)$x_1 = \frac{-1 + \sqrt{3}}{2}$或$x_2 = \frac{-1 - \sqrt{3}}{2}$ 
(6)$x_1 = \frac{1 + \sqrt{6}}{5}$或$x_2 = \frac{1 - \sqrt{6}}{5}$