第36页

信息发布者:
解:如图,由题意,得​$ DB// AE// CO,$​
∴​$∠DBC=∠BCO = 36.9°,$​​$∠EAC=∠ACO = 30°。$​
∵​$ $​在​$ Rt\triangle AOC $​中,​$AC = 24m,$​
∴​$AO=\frac {1}{2}AC = 12m,$​​$CO = AC·\mathrm {cos}30°=12\sqrt {3}m。$​
∴​$ $​在​$ Rt\triangle BOC $​中,​$BO = CO·\mathrm {tan}36.9°≈12\sqrt {3}×0.75 = 9\sqrt {3}(\mathrm {m})。$​
∴​$AB = BO - AO = 9\sqrt {3}-12≈3.6(\mathrm {m})。$​
答:无人机从点​$ A $​到点​$ B $​的上升高度​$ AB $​约为​$ 3.6m 。$​

解:
​$ (1) $​设​$ CD = xm。$​
∵​$DE = 36m,$​
∴​$CE = CD + DE = (x + 36)m。$​
∵​$EC \perp AB,$​
∴​$∠BCE = ∠ACD = 90^\circ 。$​
​$ $​在​$ Rt\triangle BCD $​中,​$∠CDB = 45^\circ ,$​​$tan ∠CDB = \frac {BC}{CD},$​
∴​$BC = CD ·\mathrm {tan}45^\circ = x\ \mathrm {·}1 = xm。$​
​$ $​在​$ Rt\triangle BCE $​中,​$∠CEB = 31^\circ ,$​​$tan ∠CEB = \frac {BC}{CE},$​
∴​$BC = CE ·\mathrm {tan}31^\circ ≈(x + 36) ×0.6 = 0.6x + 21.6。$​
∴​$x = 0.6x + 21.6,$​解得​$ x = 54。$​
答:线段​$CD$​的长约为​$54m。$​
​$ (2) $​在​$ Rt\triangle ACD $​中,​$∠CDA = 6^\circ ,$​​$\tan ∠CDA = \frac {AC}{CD},$​
∴​$AC = CD ·\mathrm {tan}6^\circ ≈54 ×0.1 = 5.4m。$​
∵​$BC = x = 54m,$​
∴​$AB = AC + BC = 5.4 + 54 = 59.4 ≈59m。$​
答:桥塔​$AB$​的高度约为​$59m。$​