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第31页

信息发布者：

$\boldsymbol{\frac{1}{4}}$

$\boldsymbol{\frac{29}{28}}$

$\boldsymbol{\frac{11}{24}}$

$\boldsymbol{\frac{1}{2}}$

$\boldsymbol{\frac{5}{18}}$

$\boldsymbol{\frac{5}{36}}$

$\boldsymbol{\frac{5}{6}}$

$\boldsymbol{\frac{2}{3}}$

 解：

 $\begin{aligned}x+\frac{1}{9}&=\frac{2}{3}\\x&=\frac{2}{3}-\frac{1}{9}\\x&=\frac{6}{9}-\frac{1}{9}\\x&=\frac{5}{9}\end{aligned}$

 解：

 $\begin{aligned}x-\frac{5}{8}&=\frac{5}{6}\\x&=\frac{5}{6}+\frac{5}{8}\\x&=\frac{20}{24}+\frac{15}{24}\\x&=\frac{35}{24}\end{aligned}$

 解：

 $\begin{aligned}5x-\frac{5}{8}&=\frac{3}{8}\\5x&=\frac{3}{8}+\frac{5}{8}\\5x&=1\\x&=\frac{1}{5}\end{aligned}$

 解：

 $\begin{aligned}x-\frac{2}{5}+\frac{3}{5}&=\frac{2}{3}\\x+\frac{1}{5}&=\frac{2}{3}\\x&=\frac{2}{3}-\frac{1}{5}\\x&=\frac{10}{15}-\frac{3}{15}\\x&=\frac{7}{15}\end{aligned}$

 $\begin{aligned}\frac{7}{8}+\frac{1}{3}+\frac{3}{4}&=\frac{21}{24}+\frac{8}{24}+\frac{18}{24}\\&=\frac{47}{24}\end{aligned}$

 $\begin{aligned}\frac{5}{6}-\left(\frac{1}{5}+\frac{1}{3}\right)&=\frac{5}{6}-\frac{8}{15}\\&=\frac{25}{30}-\frac{16}{30}\\&=\frac{3}{10}\end{aligned}$

 $\begin{aligned}5-\frac{5}{11}-\frac{17}{11}&=5-\left(\frac{5}{11}+\frac{17}{11}\right)\\&=5-2\\&=3\end{aligned}$

$\frac {23}{15}-\frac {7}{12}+\frac {7}{15}-\frac {5}{12}$

$=(\frac {23}{15}+\frac {7}{15})-(\frac {7}{12}+\frac {5}{12})$

$=2-1$

$=1$

 $\begin{aligned}\frac{10}{21}-\left(1-\frac{11}{21}\right)&=\frac{10}{21}+\frac{11}{21}-1\\&=1-1\\&=0\end{aligned}$

 $\begin{aligned}\frac{2}{3}-\left(\frac{5}{13}-\frac{1}{3}\right)-\frac{8}{13}&=\left(\frac{2}{3}+\frac{1}{3}\right)-\left(\frac{5}{13}+\frac{8}{13}\right)\\&=1-1\\&=0\end{aligned}$