解:∵$3x^2-3=3(x^2-1)=3(x-1)(x+1),$$x-1=x-1$
∴两个分母的公因式$a=x-1,$最简公分母$b=3(x-1)(x+1)$
$ $由$\frac {b}{a}=3,$得$\frac {3(x-1)(x+1)}{x-1}=3(x+1)=3$
$ $解得$x=0$
∴将$x=0$代入分式:$\frac {1}{3x^2-3}=\frac {1}{3×0^2-3}=-\frac {1}{3}$
$ \frac {2}{x-1}=\frac {2}{0-1}=-2$
∴这两个分式的值分别为$-\frac {1}{3}$和$-2。$