原式$=1-(\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{110}+\frac{1}{132})$
$=1-(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\dots+\frac{1}{11}-\frac{1}{12})$
$=1-(\frac{1}{4}-\frac{1}{12})$
$=1-\frac{1}{6}$
$=\frac{5}{6}$