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解:等式两边同时减去1,得
$1+2x-1=3-1,$
化简得 $2x=2,$
等式两边同时除以2,得
$x=1。$
解:等式两边同时减去$2x,$得
$2x+3-2x=3x-2x,$
化简得 $3=x,$
即 $x=3。$
解:等式两边同时乘6,得
$\dfrac{1}{6}x × 6 = \dfrac{1}{3} × 6,$
化简得 $x=2。$
解:等式两边同时减去1,得
$-\dfrac{1}{2}x +1 -1 = -3 -1,$
化简得 $-\dfrac{1}{2}x = -4,$
等式两边同时乘$-2,$得
$x=8。$
解:
(1)把$m=4$代入$\dfrac{1}{2}y + m = my - m,$得
$\dfrac{1}{2}y + 4 = 4y - 4$
移项,得$\dfrac{1}{2}y - 4y = -4 - 4$
合并同类项,得$-\dfrac{7}{2}y = -8$
系数化为1,得$y=\dfrac{16}{7}$
(2)把$y=4$代入$\dfrac{1}{2}y + m = my - m,$得
$\dfrac{1}{2} × 4 + m = 4m - m$
化简得$2 + m = 3m$
移项,得$m - 3m = -2$
合并同类项,得$-2m = -2$
系数化为1,得$m=1$
等式的基本性质2
等式的基本性质1
解:​$(2)$​设​$x = 0.\dot {4},$​①
​$10x = 10×0.\dot {4},$​②
​$10x = 4.\dot {4},$​③
​$10x = 4 + 0.\dot {4},$​④
​$10x = 4 + x,$​⑤
​$9x = 4,$​⑥
​$x = \frac {4}{9}。$​⑦
设​$y = 2.\dot {5},$​①
​$10y = 10×2.\dot {5},$​②
​$10y = 25.\dot {5},$​③
​$10y = 23 + 2.\dot {5},$​④
​$10y = 23 + y,$​⑤
​$9y = 23,$​⑥
​$y = \frac {23}{9}。$​⑦