1. 计算:
(1)$(-3)^{2}×2^{3}-(-4)÷2;$ (2)$4×(-\frac {3}{2})^{2}-5÷\frac {1}{2}×(-2);$
(3)$-3^{2}÷3-\frac {2}{3}×12;$ (4)$(-\frac {1}{2})^{2}×2^{3}-(-1)^{3}×6;$
(5)$(-2)^{2}+(4-7)÷\frac {3}{2}-|-1|;$ (6)$-2^{2}÷(-4)-3×(-1)^{2}-(-4);$
(7)$-3^{2}÷(-2)^{3}×|-1\frac {1}{3}|×6÷(-2)^{4};$
(8)$-(\frac {2}{3})^{2}×18-2×(-\frac {1}{5})÷\frac {2}{5}+|-8|×0.5^{2}+1\frac {7}{9}×(-1\frac {1}{2})^{2}.$
(1)$(-3)^{2}×2^{3}-(-4)÷2;$ (2)$4×(-\frac {3}{2})^{2}-5÷\frac {1}{2}×(-2);$
(3)$-3^{2}÷3-\frac {2}{3}×12;$ (4)$(-\frac {1}{2})^{2}×2^{3}-(-1)^{3}×6;$
(5)$(-2)^{2}+(4-7)÷\frac {3}{2}-|-1|;$ (6)$-2^{2}÷(-4)-3×(-1)^{2}-(-4);$
(7)$-3^{2}÷(-2)^{3}×|-1\frac {1}{3}|×6÷(-2)^{4};$
(8)$-(\frac {2}{3})^{2}×18-2×(-\frac {1}{5})÷\frac {2}{5}+|-8|×0.5^{2}+1\frac {7}{9}×(-1\frac {1}{2})^{2}.$
答案:1.(1)74 (2)29 (3)-11 (4)8 (5)1 (6)2 (7)$\frac{9}{16}$ (8)-1
解析:
(1)解:$(-3)^{2}×2^{3}-(-4)÷2$
$=9×8 - (-2)$
$=72 + 2$
$=74$
(2)解:$4×(-\frac{3}{2})^{2}-5÷\frac{1}{2}×(-2)$
$=4×\frac{9}{4} - 5×2×(-2)$
$=9 - (-20)$
$=9 + 20$
$=29$
(3)解:$-3^{2}÷3 - \frac{2}{3}×12$
$=-9÷3 - 8$
$=-3 - 8$
$=-11$
(4)解:$(-\frac{1}{2})^{2}×2^{3}-(-1)^{3}×6$
$=\frac{1}{4}×8 - (-1)×6$
$=2 + 6$
$=8$
(5)解:$(-2)^{2}+(4 - 7)÷\frac{3}{2}-|-1|$
$=4 + (-3)×\frac{2}{3} - 1$
$=4 - 2 - 1$
$=1$
(6)解:$-2^{2}÷(-4)-3×(-1)^{2}-(-4)$
$=-4÷(-4) - 3×1 + 4$
$=1 - 3 + 4$
$=2$
(7)解:$-3^{2}÷(-2)^{3}×|-1\frac{1}{3}|×6÷(-2)^{4}$
$=-9÷(-8)×\frac{4}{3}×6÷16$
$=\frac{9}{8}×\frac{4}{3}×6×\frac{1}{16}$
$=\frac{3}{2}×6×\frac{1}{16}$
$=9×\frac{1}{16}$
$=\frac{9}{16}$
(8)解:$-(\frac{2}{3})^{2}×18 - 2×(-\frac{1}{5})÷\frac{2}{5}+|-8|×0.5^{2}+1\frac{7}{9}×(-1\frac{1}{2})^{2}$
$=-\frac{4}{9}×18 - 2×(-\frac{1}{5})×\frac{5}{2}+8×\frac{1}{4}+\frac{16}{9}×\frac{9}{4}$
$=-8 + 1 + 2 + 4$
$=-1$
$=9×8 - (-2)$
$=72 + 2$
$=74$
(2)解:$4×(-\frac{3}{2})^{2}-5÷\frac{1}{2}×(-2)$
$=4×\frac{9}{4} - 5×2×(-2)$
$=9 - (-20)$
$=9 + 20$
$=29$
(3)解:$-3^{2}÷3 - \frac{2}{3}×12$
$=-9÷3 - 8$
$=-3 - 8$
$=-11$
(4)解:$(-\frac{1}{2})^{2}×2^{3}-(-1)^{3}×6$
$=\frac{1}{4}×8 - (-1)×6$
$=2 + 6$
$=8$
(5)解:$(-2)^{2}+(4 - 7)÷\frac{3}{2}-|-1|$
$=4 + (-3)×\frac{2}{3} - 1$
$=4 - 2 - 1$
$=1$
(6)解:$-2^{2}÷(-4)-3×(-1)^{2}-(-4)$
$=-4÷(-4) - 3×1 + 4$
$=1 - 3 + 4$
$=2$
(7)解:$-3^{2}÷(-2)^{3}×|-1\frac{1}{3}|×6÷(-2)^{4}$
$=-9÷(-8)×\frac{4}{3}×6÷16$
$=\frac{9}{8}×\frac{4}{3}×6×\frac{1}{16}$
$=\frac{3}{2}×6×\frac{1}{16}$
$=9×\frac{1}{16}$
$=\frac{9}{16}$
(8)解:$-(\frac{2}{3})^{2}×18 - 2×(-\frac{1}{5})÷\frac{2}{5}+|-8|×0.5^{2}+1\frac{7}{9}×(-1\frac{1}{2})^{2}$
$=-\frac{4}{9}×18 - 2×(-\frac{1}{5})×\frac{5}{2}+8×\frac{1}{4}+\frac{16}{9}×\frac{9}{4}$
$=-8 + 1 + 2 + 4$
$=-1$