零五网 全部参考答案 启东中学作业本 2025年启东中学作业本七年级数学上册人教版 第7页解析答案
计算:
(1)$(-3)-(+\frac {1}{3})+5-(-1\frac {1}{3})$; (2)$(-12)-5+(-14)-(-39)$;
(3)$0.25+(-\frac {1}{8})-\frac {3}{4}-|-\frac {7}{8}|$; (4)$\frac {5}{6}+(-2\frac {1}{2})-(-1\frac {1}{6})-(+0.5)$;
(5)$5\frac {3}{4}-(-4\frac {2}{3})-5.75+(-7\frac {2}{3})$; (6)$\frac {2}{9}-(-1\frac {5}{6})+(-1\frac {2}{9})-\frac {1}{3}$;
(7)$(-301)+125+301+(-75)$; (8)$(-8)-(-15)+(-9)-(-12)$;
(9)$-\frac {31}{3}-(-\frac {58}{7})+(-\frac {9}{7})-(+\frac {32}{3})$; (10)$(-4\frac {7}{9})-(-3\frac {1}{6})-(+\frac {2}{9})+(6\frac {1}{6})$.
答案:(1)3 (2)8 (3)-1.5 (4)-1 (5)-3 (6)$\frac{1}{2}$ (7)50 (8)10 (9)-14 (10)$4\frac{1}{3}$
解析:
(1)
$\begin{aligned}(-3)-\left(+\frac{1}{3}\right)+5-\left(-1\frac{1}{3}\right)&=-3 - \frac{1}{3} + 5 + 1\frac{1}{3}\\&=(-3 + 5) + \left(-\frac{1}{3} + 1\frac{1}{3}\right)\\&=2 + 1\\&=3\end{aligned}$
(2)
$\begin{aligned}(-12)-5+(-14)-(-39)&=-12 - 5 - 14 + 39\\&=(-12 - 5 - 14) + 39\\&=-31 + 39\\&=8\end{aligned}$
(3)
$\begin{aligned}0.25+\left(-\frac{1}{8}\right)-\frac{3}{4}-\left|-\frac{7}{8}\right|&=\frac{1}{4} - \frac{1}{8} - \frac{3}{4} - \frac{7}{8}\\&=\left(\frac{1}{4} - \frac{3}{4}\right) + \left(-\frac{1}{8} - \frac{7}{8}\right)\\&=-\frac{1}{2} - 1\\&=-\frac{3}{2}\\&=-1.5\end{aligned}$
(4)
$\begin{aligned}\frac{5}{6}+\left(-2\frac{1}{2}\right)-\left(-1\frac{1}{6}\right)-(+0.5)&=\frac{5}{6} - 2\frac{1}{2} + 1\frac{1}{6} - \frac{1}{2}\\&=\left(\frac{5}{6} + 1\frac{1}{6}\right) + \left(-2\frac{1}{2} - \frac{1}{2}\right)\\&=2 - 3\\&=-1\end{aligned}$
(5)
$\begin{aligned}5\frac{3}{4}-\left(-4\frac{2}{3}\right)-5.75+\left(-7\frac{2}{3}\right)&=5.75 + 4\frac{2}{3} - 5.75 - 7\frac{2}{3}\\&=(5.75 - 5.75) + \left(4\frac{2}{3} - 7\frac{2}{3}\right)\\&=0 - 3\\&=-3\end{aligned}$
(6)
$\begin{aligned}\frac{2}{9}-\left(-1\frac{5}{6}\right)+\left(-1\frac{2}{9}\right)-\frac{1}{3}&=\frac{2}{9} + 1\frac{5}{6} - 1\frac{2}{9} - \frac{1}{3}\\&=\left(\frac{2}{9} - 1\frac{2}{9}\right) + \left(1\frac{5}{6} - \frac{1}{3}\right)\\&=-1 + 1\frac{1}{2}\\&=\frac{1}{2}\end{aligned}$
(7)
$\begin{aligned}(-301)+125+301+(-75)&=(-301 + 301) + (125 - 75)\\&=0 + 50\\&=50\end{aligned}$
(8)
$\begin{aligned}(-8)-(-15)+(-9)-(-12)&=-8 + 15 - 9 + 12\\&=(-8 - 9) + (15 + 12)\\&=-17 + 27\\&=10\end{aligned}$
(9)
$\begin{aligned}-\frac{31}{3}-\left(-\frac{58}{7}\right)+\left(-\frac{9}{7}\right)-\left(+\frac{32}{3}\right)&=-\frac{31}{3} + \frac{58}{7} - \frac{9}{7} - \frac{32}{3}\\&=\left(-\frac{31}{3} - \frac{32}{3}\right) + \left(\frac{58}{7} - \frac{9}{7}\right)\\&=-\frac{63}{3} + \frac{49}{7}\\&=-21 + 7\\&=-14\end{aligned}$
(10)
$\begin{aligned}\left(-4\frac{7}{9}\right)-\left(-3\frac{1}{6}\right)-\left(+\frac{2}{9}\right)+\left(6\frac{1}{6}\right)&=-4\frac{7}{9} + 3\frac{1}{6} - \frac{2}{9} + 6\frac{1}{6}\\&=\left(-4\frac{7}{9} - \frac{2}{9}\right) + \left(3\frac{1}{6} + 6\frac{1}{6}\right)\\&=-5 + 9\frac{1}{3}\\&=4\frac{1}{3}\end{aligned}$
上一页 下一页