第123页

信息发布者:
C
B
4
$​​\sqrt{2}​​$
$​​\frac{\sqrt{5}}{4}​​$
$​​\frac{1}{2} \sqrt{17}​​$
$​​2\sqrt{5}​​$
$​​8\sqrt2​​$
$​​ \begin{aligned}解:原式&= \sqrt{\frac{49}{9}} \\ &=\frac{7}{3} \\ \end{aligned}​​$
$​​ \begin{aligned}解:原式&=\frac{9×5\sqrt{5}}{12} \\ &=\frac{15\sqrt{5}}{4} \\ \end{aligned}​​$
$ \begin{aligned}​​ 解:原式&=\sqrt{\frac{(11b^2)^2·b}{(4a)^2}} \\ &=\frac{11b^2\sqrt{b}}{4a} \\ \end{aligned}$
$ ​​$
$​​ \begin{aligned}解:原式&=\frac{\sqrt{2^2xy·x}}{\sqrt{2^2xy}} \\ &=\sqrt x \\ \end{aligned}​​$
$​​ \begin{aligned}解:原式&=\frac{3\sqrt{6}}{\sqrt{3}} \\ &=3\sqrt{2} \\ \end{aligned}​​$
$​​ \begin{aligned}解:原式&=\frac{\sqrt2}{3×2} \\ &=\frac{\sqrt{2}}{6} \\ \end{aligned}​​$
$​​ \begin{aligned}解:原式&=\frac{5\sqrt n·\sqrt n}{3\sqrt n} \\ &=\frac{5\sqrt{n}}{3} \\ \end{aligned}​​$
$​​ \begin{aligned}解:原式&=\frac{2xy\sqrt{2x}}{2x} \\ &=y\sqrt{2x} \\ \end{aligned}​​$
$​​ \begin{aligned}解:原式&= \sqrt{\frac{16}{5}×\frac{5}{8}} \\ &=\sqrt2 \\ \end{aligned}​​$
$​​ \begin{aligned}解:原式&= \sqrt{\frac{b}{5}×\frac{20a^2}{b}} \\ &= \sqrt{4a^2} \\ &=2|a| \\ \end{aligned}​​$
$​​ \begin{aligned} 解:原式&=\sqrt{\frac{6a^2}{24a}} \\ &=\sqrt{\frac{a}{4}} \\ &=\frac{\sqrt a}{2} \\ \end{aligned}​​$
$​​ \begin{aligned}解:原式&=\frac{1}{2}\sqrt{xy·\frac{x}{y^3}} \\ &=\frac{1}{2}\sqrt{\frac{x^2}{y^2}} \\ &=\frac{x}{2y} \\ \end{aligned}​​$
$​​ \begin{aligned}解:原式&= \sqrt{\frac{b}{a}·\frac{1}{ab}·\frac{a^3}{b^2}} \\ &=\sqrt{\frac{a}{b^2}} \\ &=\frac{\sqrt a}{b} \\ \end{aligned}​​$
$\sqrt2$