解:$(1)x(5x+4)-(5x+4)=0$
$(5x+4)(x-1)=0$
$x_1= -\frac {4}{5}$,$x_2=1$
$(2)$∵$a=1$,$b=-2\sqrt {5}$,$c=2$
∴$△=b²-4ac=(-2\sqrt 5)²-4×1×2=12>0$
∴$x=\frac {2\sqrt 5±\sqrt {12}}{2}$
∴$x_{1}=\sqrt {5}+\sqrt {3}$,$x_{2}=\sqrt {5}-\sqrt {3}$