证明:$(3)$过点$O$作$BC$的平行线,交$CA$的延长线于点$F$
∵$OF// BC,$∴$∠ACB = ∠F$
∵$A,$$B$两点的极坐标分别记为$(a,$$0°),$$(2a,$$0°)$
∴$OB = 2a,$$OA = a,$即$OA = AB$
$ $在$\triangle AOF $和$\triangle ABC$中
$ \begin {cases}∠OAF=∠BAC \\∠F=∠ACB \\OA = AB\end {cases}$
∴$\triangle AOF≌\triangle ABC(\mathrm {AAS})$
∴$OF = BC$
又∵$OE = BC,$∴$OE = OF,$∴$∠F=∠OEA$
∴$∠OEA=∠ACB$