解:由题意,得$7 - 3m = 2m - 3$或$7 - 3m + 2m - 3 = 0。$
当$7 - 3m = 2m - 3$时,移项可得$7 + 3 = 2m + 3m,$即$5m = 10,$解得$m = 2。$
此时$7 - 3m = 7 - 3\times2 = 1,$$2m - 3 = 2\times2 - 3 = 1,$这个正数为$1^{2}=1。$
当$7 - 3m + 2m - 3 = 0$时,合并同类项可得$4 - m = 0,$解得$m = 4。$
此时$7 - 3m = 7 - 3\times4 = - 5,$$2m - 3 = 2\times4 - 3 = 5,$又$(\pm5)^{2}=25,$所以这个正数为$25。$
综上,这个正数为$1$或$25。$