解:
$\begin {aligned}&2\frac {2}{5}+(-2\frac {7}{8})+(-1\frac {5}{12})+4\frac {3}{5}+(-1\frac {1}{8})+(-3\frac {7}{12})\\=&(2\frac {2}{5}+4\frac {3}{5})+[(-2\frac {7}{8})+(-1\frac {1}{8})]+[(-1\frac {5}{12})+(-3\frac {7}{12})]\\=&7+(-4)+(-5)\\=&7-(4 + 5)\\=& - 2\end {aligned}$