证明:$(1)$在$Rt\triangle ABF $和$Rt\triangle CDE$中
$\begin {cases}AF = CE\\AB = CD\end {cases}$
∴$Rt\triangle ABF≌ Rt\triangle CDE(\mathrm {HL})$
∴$∠A = ∠C$
∵点$A,$$F,$$E,$$C$在同一条直线上,∴$AB// CD$
解:$(2)$∵$\triangle ABG ≌ \triangle CDG(\mathrm {AAS})$
∴$DG = BG = 10$