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信息发布者:
解:
(1)由题意得$AC=AB+BC=(a+b)+(a-b)=2a;$
(2)$CD=BD-BC=(4a-2b)-(a-b)=3a-b;$
(3)$CD-AB=(3a-b)-(a+b)=2a-2b=2(a-b)=2BC,$即$CD-AB=2BC$
解:
(1)$A+3B=3x^{2}+2xy-2x-1+3(-x^{2}+xy-1)=3x^{2}+2xy-2x-1-3x^{2}+3xy-3=5xy-2x-4;$
(2)因为$A+3B=(5y-2)x-4$与$x$取值无关,所以$5y-2=0,$解得$y=\frac{2}{5}$
$\pi-3.14$
$b-a$
解:
(3)原式$=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\cdots+\frac{1}{2022}-\frac{1}{2023}=1-\frac{1}{2023}=\frac{2022}{2023};$
(4)由数轴知$a=-2,$$b=-1,$$c=2,$原式$=|-2|+|-2+(-1)|-2|-1-2|=2+3-6=-1$