$ (1)$解方程:$4(2 - y) + 2(3y - 1) = 7$
去括号得:$8 - 4y + 6y - 2 = 7$
合并同类项得:$6 + 2y = 7$
移项得:$2y = 1$
解得:$y = \frac {1}{2}$
$ (2)$解方程:$\frac {2x + 1}{3} - 1 = \frac {2x - 3}{4}$
$ $去分母$($两边乘$12)$得:$4(2x + 1) - 12 = 3(2x - 3)$
去括号得:$8x + 4 - 12 = 6x - 9$
合并同类项得:$8x - 8 = 6x - 9$
移项得:$2x = -1$
解得:$x = -\frac {1}{2}$