解:$\begin {cases} 2025x + 2024y = 2023 ① \\2023x + 2022y = 2021 ② \end {cases}$
$①-②$得$2x + 2y = 2,$即$x + y = 1 ③$
$③×2022$得$2022x + 2022y = 2022 ④$
$②-④$得$x = -1$
将$x = -1$代入$③$得$-1 + y = 1,$解得$y = 2,$
∴方程组的解为$\begin {cases} x = -1 \\y = 2 \end {cases}$