$BD=2DA,$$BD$:$DA=2$:$1$
$S_{△ B D C} $:$S_{△ A D C}=2$:$1 ,$$S_{△ B D C}=\frac {2} {3} S_{△ A B C}$
$BC=4BE,$$BE$:$BC=1$:$4,$$EC$:$BC=3$:$4$
$S_{△ D E C}$:$S_{△ B D C}=3 $:$ 4,$$S_{△ D EC}=\frac {3} {4}S_{△ B D C}$
$DF$:$FC=3$:$2,$$S_{△ D E F} $:$ S_{△ C F E} = 3 $:$ 2 ,$$S_{△ D E F} =\frac {3} {5}S_{△ D E C}$
$S_{△ D E F} = \frac {3} {5} × \frac {3} {4} × \frac {2} {3}×24=7.2($平方厘米$)$