零五网 全部参考答案 启东中学作业本 2025年启东中学作业本七年级数学上册江苏版 第16页解析答案
计算:
(1)$-5+8-12+6$; (2)$2-[(-2)-(-4)]$;
(3)$7-(-6)+(-4)× (-3)$; (4)$\frac {3}{2}× (-\frac {1}{2})÷ (-4\frac {1}{2})$;
(5)$\frac {4}{3}× (-\frac {1}{6})-\frac {5}{3}÷ (-\frac {15}{7})$; (6)$-3× (-2)^{2}-1+(-\frac {1}{2})^{3}$;
(7)$25÷ \frac {5}{6}× (-\frac {2}{5})+(-2)× (-1)^{2024}$; (8)$-2^{3}÷ (-\frac {1}{6})-\frac {1}{4}× (-2)^{2}$;
(9)$-4^{2}× |\frac {1}{2}-1|-(-5)+2$; (10)$-3^{2}+(-12)× |-\frac {1}{2}|-6÷ (-1)$.
答案:(1)$-3$ (2)$0$ (3)$25$ (4)$\frac{1}{6}$ (5)$\frac{5}{9}$ (6)$-13\frac{1}{8}$ (7)$-14$ (8)$47$ (9)$-1$ (10)$-9$
解析:
(1)解:$-5+8-12+6$
$=(-5-12)+(8+6)$
$=-17+14$
$=-3$
(2)解:$2-[(-2)-(-4)]$
$=2-(-2+4)$
$=2-2$
$=0$
(3)解:$7-(-6)+(-4)×(-3)$
$=7+6+12$
$=13+12$
$=25$
(4)解:$\frac{3}{2}×(-\frac{1}{2})÷(-4\frac{1}{2})$
$=\frac{3}{2}×(-\frac{1}{2})÷(-\frac{9}{2})$
$=\frac{3}{2}×(-\frac{1}{2})×(-\frac{2}{9})$
$=\frac{3×1×2}{2×2×9}$
$=\frac{1}{6}$
(5)解:$\frac{4}{3}×(-\frac{1}{6})-\frac{5}{3}÷(-\frac{15}{7})$
$=-\frac{2}{9}-\frac{5}{3}×(-\frac{7}{15})$
$=-\frac{2}{9}+\frac{7}{9}$
$=\frac{5}{9}$
(6)解:$-3×(-2)^2 -1+(-\frac{1}{2})^3$
$=-3×4 -1+(-\frac{1}{8})$
$=-12 -1-\frac{1}{8}$
$=-13-\frac{1}{8}$
$=-13\frac{1}{8}$
(7)解:$25÷\frac{5}{6}×(-\frac{2}{5})+(-2)×(-1)^{2024}$
$=25×\frac{6}{5}×(-\frac{2}{5})+(-2)×1$
$=30×(-\frac{2}{5})-2$
$=-12 -2$
$=-14$
(8)解:$-2^3÷(-\frac{1}{6})-\frac{1}{4}×(-2)^2$
$=-8×(-6)-\frac{1}{4}×4$
$=48 -1$
$=47$
(9)解:$-4^2×|\frac{1}{2}-1|-(-5)+2$
$=-16×\frac{1}{2}+5+2$
$=-8 +5+2$
$=-1$
(10)解:$-3^2+(-12)×|-\frac{1}{2}|-6÷(-1)$
$=-9+(-12)×\frac{1}{2}+6$
$=-9 -6 +6$
$=-9$
上一页 下一页