1. 计算下面各题。
$2-\frac{8}{15}×\frac{9}{16}$
$1-\frac{8}{9}×\frac{3}{8}×\frac{1}{7}$
$[1-(\frac{3}{4}-\frac{3}{8})]÷\frac{5}{6}$
$5-(\frac{6}{7}÷\frac{3}{14}+\frac{6}{13})$
$6÷(\frac{3}{5}+\frac{3}{4})$
$1-\frac{6}{7}÷\frac{3}{7}×\frac{3}{16}$
$2-\frac{8}{15}×\frac{9}{16}$
$1-\frac{8}{9}×\frac{3}{8}×\frac{1}{7}$
$[1-(\frac{3}{4}-\frac{3}{8})]÷\frac{5}{6}$
$5-(\frac{6}{7}÷\frac{3}{14}+\frac{6}{13})$
$6÷(\frac{3}{5}+\frac{3}{4})$
$1-\frac{6}{7}÷\frac{3}{7}×\frac{3}{16}$
答案：$ =2-\frac 3{10}$
$ =1\frac 7{10}$
$ =1-\frac 13×\frac 17$
$ =1-\frac 1{21}$
$ =\frac {20}{21}$
$ =[1-\frac 38]×\frac 65$
$ =\frac 58×\frac 65$
$ =\frac 34$
$ =5-(\frac 67×\frac {14}3+\frac 6{13})$
$ =5-4-\frac 6{13}$
$ =\frac 7{13}$
$ =6÷(\frac {12}{20}+\frac {15}{20})$
$ =6÷\frac {27}{20}$
$ =6×\frac {20}{27}$
$ =\frac {40}9$
$ =1-\frac 67×\frac 73×\frac 3{16}$
$ =1-2×\frac 3{16}$
$ =1-\frac 38$
$ =\frac 58$
$ =1\frac 7{10}$
$ =1-\frac 13×\frac 17$
$ =1-\frac 1{21}$
$ =\frac {20}{21}$
$ =[1-\frac 38]×\frac 65$
$ =\frac 58×\frac 65$
$ =\frac 34$
$ =5-(\frac 67×\frac {14}3+\frac 6{13})$
$ =5-4-\frac 6{13}$
$ =\frac 7{13}$
$ =6÷(\frac {12}{20}+\frac {15}{20})$
$ =6÷\frac {27}{20}$
$ =6×\frac {20}{27}$
$ =\frac {40}9$
$ =1-\frac 67×\frac 73×\frac 3{16}$
$ =1-2×\frac 3{16}$
$ =1-\frac 38$
$ =\frac 58$
2. 用简便方法计算。
$\frac{6}{5}×\frac{2}{15}+\frac{2}{15}×\frac{4}{5}$
$\frac{6}{11}÷4-\frac{1}{4}×\frac{5}{11}$
$\frac{7}{9}×\frac{7}{11}+\frac{7}{9}×\frac{4}{11}$
$\frac{32}{33}×32$
$\frac{6}{5}×\frac{2}{15}+\frac{2}{15}×\frac{4}{5}$
$\frac{6}{11}÷4-\frac{1}{4}×\frac{5}{11}$
$\frac{7}{9}×\frac{7}{11}+\frac{7}{9}×\frac{4}{11}$
$\frac{32}{33}×32$
答案：$ =(\frac 65+\frac 45)×\frac 2{15}$
$ =2×\frac 2{15}$
$ =\frac 4{15}$
$ =\frac 6{11}×\frac 14-\frac 14×\frac 5{11}$
$ =\frac 14×(\frac 6{11}-\frac 5{11})$
$ =\frac 14×\frac 1{11}$
$ =\frac 1{44}$
$ =(\frac 7{11}+\frac 4{11})×\frac 79$
$ =1×\frac 79$
$ =\frac 79$
$ =\frac {32}{33}×(33-1)$
$ =\frac {32}{33}×33-\frac {32}{33}$
$ =32-\frac {32}{33}$
$ =31\frac 1{33}$
$ =2×\frac 2{15}$
$ =\frac 4{15}$
$ =\frac 6{11}×\frac 14-\frac 14×\frac 5{11}$
$ =\frac 14×(\frac 6{11}-\frac 5{11})$
$ =\frac 14×\frac 1{11}$
$ =\frac 1{44}$
$ =(\frac 7{11}+\frac 4{11})×\frac 79$
$ =1×\frac 79$
$ =\frac 79$
$ =\frac {32}{33}×(33-1)$
$ =\frac {32}{33}×33-\frac {32}{33}$
$ =32-\frac {32}{33}$
$ =31\frac 1{33}$