证明:$\because$四边形$ABCD$是平行四边形,
$\therefore AB// CD,$$AB = CD.$$\therefore\angle ABD=\angle CDB.$
$\because AE// CF,$$\therefore\angle AEF=\angle CFE.$
$\because\angle AEB = 180^{\circ}-\angle AEF,$$\angle CFD = 180^{\circ}-\angle CFE,$
$\therefore\angle AEB=\angle CFD.$
在$\triangle ABE$和$\triangle CDF$中,
$\begin{cases}\angle AEB=\angle CFD,\\\angle ABE=\angle CDF,\\AB = CD,\end{cases}$
$\therefore\triangle ABE\cong\triangle CDF(\text{AAS}).$
$\therefore BE = DF.$