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信息发布者:
C
$F = \frac{800}{l}$
解:
(1)设$h$关于$\rho$的函数表达式为$h = \frac{k}{\rho},$
把$\rho = 1,$$h = 20$代入函数表达式,得$k = 1\times20 = 20,$
$\therefore h$关于$\rho$的函数表达式为$h = \frac{20}{\rho}.$
(2)把$h = 25$代入$h = \frac{20}{\rho},$得$25 = \frac{20}{\rho},$
解得$\rho = 0.8.$
答:该液体的密度$\rho$为$0.8\ g/cm^{3}.$
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0.6