第115页

信息发布者:
D
D
解:$\sqrt{\frac{1}{3}}\times\sqrt{27}=\sqrt{\frac{1}{3}\times27}=\sqrt{9}=3$
解:$\sqrt{48}\times\sqrt{12}=\sqrt{48\times12}=\sqrt{576}=24$
解:$\sqrt{2\frac{2}{3}}\times\sqrt{1\frac{1}{2}}=\sqrt{\frac{8}{3}}\times\sqrt{\frac{3}{2}}=\sqrt{\frac{8}{3}\times\frac{3}{2}}=\sqrt{4}=2$
解:$\sqrt{2x^{3}}\cdot\sqrt{8x}=\sqrt{2x^{3}\cdot8x}=\sqrt{16x^{4}} = 4x^{2}$
$ \begin{aligned}解:原式&=\sqrt {25}×\sqrt 2 \\ &=5\sqrt{2} \\ \end{aligned}$
$ \begin{aligned}解:原式&=\sqrt 4×\sqrt {6a} \\ &=2\sqrt{6a} \\ \end{aligned}$
$ \begin{aligned}解:原式&=\sqrt {81b^2}×\sqrt {ab} \\ &=9b\sqrt {ab} \\ \end{aligned}$
$ \begin{aligned}解:原式&=\sqrt {169} \\ &=13 \\ \end{aligned}$
$x\geqslant1$
$\sqrt{6}$
$2\sqrt{3}$
$\sqrt{5}$
$10$或$2\sqrt{7}$