证明:在$\triangle ABD$和$\triangle CBD$中,
$\begin{cases}AB = CB \\BD = BD \\AD = CD\end{cases}$
$\therefore \triangle ABD\cong\triangle CBD(SSS)$
$\therefore \angle ABD = \angle CBD,$即$BO$平分$\angle ABC。$
又$\because OE\perp AB,$$OF\perp CB,$
$\therefore OE = OF。$