第27页

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$pa + pb + pc$
B
A
$10x^{3}+5x^{2}$
$a^{3}b - ab$
$3x^{2}-4x$
解:
$\begin{aligned}-6x\cdot(x - 3y)&=-6x\cdot x+(-6x)\cdot(-3y)\\&=-6x^{2}+18xy\end{aligned}$
解:
$\begin{aligned}-4xy\cdot(xy + 3x^{2}y)&=-4xy\cdot xy+(-4xy)\cdot(3x^{2}y)\\&=-4x^{2}y^{2}-12x^{3}y^{2}\end{aligned}$
解:原式​$=-2ab·2a^2+(-2ab)·ab+(-2ab)·(-2b^2)$​
​$=-4a^3b-2a^2b^2+4ab^3$​
解:
$\begin{aligned}9a^{2}b^{2}\cdot(\frac{1}{9}a^{3}b - a^{2}b^{2}-1)&=9a^{2}b^{2}\cdot\frac{1}{9}a^{3}b-9a^{2}b^{2}\cdot a^{2}b^{2}-9a^{2}b^{2}\cdot1\\&=a^{5}b^{3}-9a^{4}b^{4}-9a^{2}b^{2}\end{aligned}$