第64页

信息发布者:
D
B
D
×
$a + b - c + d$
×
$-a + b + c - d$
$a + b + c - d$
$-a + b - c$
$a^{2}-2$
解:
$\begin{aligned}&3x - [5x - 4(2x - 1)]\\=&3x - (5x - 8x + 4)\\=&3x - 5x + 8x - 4\\=&(3x - 5x + 8x) - 4\\=&6x - 4\end{aligned}$
解:
$\begin{aligned}&-3(a^{2}-bc + b^{2})-2(-a^{2}+bc-\frac{1}{3}b^{2})\\=&-3a^{2}+3bc - 3b^{2}+2a^{2}-2bc+\frac{2}{3}b^{2}\\=&(-3a^{2}+2a^{2})+(3bc - 2bc)+(-3b^{2}+\frac{2}{3}b^{2})\\=&-a^{2}+bc-\frac{7}{3}b^{2}\end{aligned}$
解:
$\begin{aligned}&(5x^{2}y - 2xy^{2}-3xy)-(2xy + 5x^{2}y - 2xy^{2})\\=&5x^{2}y - 2xy^{2}-3xy - 2xy - 5x^{2}y + 2xy^{2}\\=&(5x^{2}y - 5x^{2}y)+(-2xy^{2}+ 2xy^{2})+(-3xy - 2xy)\\=&-5xy\end{aligned}$
当$x = -\frac{1}{5},$$y = -\frac{1}{3}$时,原式$=-5×(-\frac{1}{5})×(-\frac{1}{3})=-\frac{1}{3}$