第66页

信息发布者:
C
B
$(-\frac{32}{5},\frac{6}{5})$或$(-4,3)$
$\frac{3}{2}$
D
证明:​$(1)$​∵​$AD^2 = ED ·FD,$​
∴​$\frac {AD}{ED} = \frac {FD}{AD}。$​
又∵​$∠ADF = ∠EDA,$​
∴​$\triangle ADF \sim \triangle EDA。$​
∴​$∠F = ∠DAE。$​
∵​$∠ADB = ∠CDE,$​
∴​$∠ADB + ∠ADF = ∠CDE + ∠ADF,$​即​$∠BDF = ∠CDA。$​
∴​$\triangle BFD \sim \triangle CAD。$​
​$ (2)$​∵​$\triangle BFD \sim \triangle CAD,$​
∴​$\frac {BF}{CA} = \frac {FD}{AD}。$​
∵​$\frac {AD}{ED} = \frac {FD}{AD},$​
∴​$\frac {BF}{CA} = \frac {AD}{ED}。$​
∵​$\triangle BFD \sim \triangle CAD,$​
∴​$∠B = ∠C。$​
∴​$AB = CA。$​
∴​$\frac {BF}{AB} = \frac {AD}{ED}。$​
∴​$BF ·ED = AB ·AD。$​