证明:$(1)$∵$AD^2 = ED ·FD,$
∴$\frac {AD}{ED} = \frac {FD}{AD}。$
又∵$∠ADF = ∠EDA,$
∴$\triangle ADF \sim \triangle EDA。$
∴$∠F = ∠DAE。$
∵$∠ADB = ∠CDE,$
∴$∠ADB + ∠ADF = ∠CDE + ∠ADF,$即$∠BDF = ∠CDA。$
∴$\triangle BFD \sim \triangle CAD。$
$ (2)$∵$\triangle BFD \sim \triangle CAD,$
∴$\frac {BF}{CA} = \frac {FD}{AD}。$
∵$\frac {AD}{ED} = \frac {FD}{AD},$
∴$\frac {BF}{CA} = \frac {AD}{ED}。$
∵$\triangle BFD \sim \triangle CAD,$
∴$∠B = ∠C。$
∴$AB = CA。$
∴$\frac {BF}{AB} = \frac {AD}{ED}。$
∴$BF ·ED = AB ·AD。$