解:
(1) 将$\begin{cases}x=-2\\y=3\end{cases}$代入$ax - by = 5,$得:
$-2a - 3b = 5,$即$2a + 3b = -5,$
则$4a + 6b = 2(2a + 3b)=2×(-5)=-10。$
(2) 由$2a + 3b = -5,$得$6a + 9b = 3(2a + 3b)=-15,$
将$4a + 6b=-10,$$6a + 9b=-15$代入方程组:
$\begin{cases}2m + 3n = -10 + 7=-3&①\\2m - 3n = -15 - 6=-21&②\end{cases}$
①$+$②得:$4m=-24,$解得$m=-6,$
将$m=-6$代入①得:$2×(-6)+3n=-3,$解得$n=3。$
所以方程组的解为$\begin{cases}m=-6\\n=3\end{cases}$