解:
$ (1) $由题意,得$6+3m<0,$∴$m<-2$
$ (2) $由题意,得$\begin {cases}6+3m≠0\\n -4<0\end {cases},$∴$m≠-2$且$n<4$
$ (3) $由题意,得$\begin {cases}6+3m≠0\\n -4=0\end {cases},$∴$m≠-2$且$n=4$
$ (4) $由题意,得$\begin {cases}6+3m=4\\n -4≠0\end {cases},$∴$m=-\frac {2}{3}$且$n≠4$