解:
(1) 连接$AB。$
在$△ ABC$和$△ ABD$中,
$\begin{cases} AC=AD,\\ AB=AB,\\ BC=BD, \end{cases}$
$\therefore △ ABC ≌ △ ABD(\mathrm{SSS}),$
$\therefore ∠ C = ∠ D。$
(2) $\because △ ABC ≌ △ ABD,$
$\therefore ∠ CAB = ∠ DAB = \frac{1}{2}∠ CAD,$$∠ ABC = ∠ ABD。$
$\because ∠ CBD=120°,$
$\therefore ∠ ABC = \frac{1}{2}(360° - ∠ CBD)=120°。$
$\because$ 在$△ ABC$中,$∠ C=28°,$
$\therefore ∠ CAB = 180° - 120° -28° =32°,$
$\therefore ∠ CAD = 2∠ CAB =64°,$即$∠ A=64°$