第15页

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$AB// DC$
解:
(1) $\because AD=BE,$
$\therefore AD+BD=BE+BD,$即$AB=DE。$
在$△ ABC$和$△ DEF$中,
$\begin{cases} AB=DE,\\ AC=DF,\\ BC=EF, \end{cases}$
$\therefore △ ABC ≌ △ DEF(\mathrm{SSS})。$
(2) $\because △ ABC ≌ △ DEF,$$∠ A=55°,$
$\therefore ∠ A = ∠ FDE = 55°。$
$\because △ DEF$的内角和为$180°,$$∠ E=45°,$
$\therefore ∠ F = 180° - (∠ FDE + ∠ E) = 180° -(55° +45°)=80°$
解:
(1) 连接$AB。$
在$△ ABC$和$△ ABD$中,
$\begin{cases} AC=AD,\\ AB=AB,\\ BC=BD, \end{cases}$
$\therefore △ ABC ≌ △ ABD(\mathrm{SSS}),$
$\therefore ∠ C = ∠ D。$
(2) $\because △ ABC ≌ △ ABD,$
$\therefore ∠ CAB = ∠ DAB = \frac{1}{2}∠ CAD,$$∠ ABC = ∠ ABD。$
$\because ∠ CBD=120°,$
$\therefore ∠ ABC = \frac{1}{2}(360° - ∠ CBD)=120°。$
$\because$ 在$△ ABC$中,$∠ C=28°,$
$\therefore ∠ CAB = 180° - 120° -28° =32°,$
$\therefore ∠ CAD = 2∠ CAB =64°,$即$∠ A=64°$

C