用适当的方法解下列方程组：
(1)$\begin{cases}x = y + 1, \\ 3x - 2y = 2;\end{cases}$ (2)$\begin{cases}3x + 4y = 19, \\ x - y = 4;\end{cases}$
(3)$\begin{cases}2x + 3y = -5, \\ 3x - 2y = 12;\end{cases}$ (4)$\begin{cases}\dfrac{x}{2} + \dfrac{y}{3} = -2, \\ 3x - 4y = 6;\end{cases}$
(5)$\begin{cases}6x - 5y = 27, \\ 5x - 2y = 16;\end{cases}$ (6)$\begin{cases}8x - 7y = 18, \\ 3x + 2y = -21;\end{cases}$
(7)$\begin{cases}4(x - y - 1) = 3(1 - y) - 2, \\ \dfrac{x}{2} + \dfrac{y}{3} = 2;\end{cases}$ (8)$\begin{cases}\dfrac{x - 1}{2} - 2y = 4, \\ 1 - \dfrac{y - x}{3} = 3.\end{cases}$
(1)$\begin{cases}x = y + 1, \\ 3x - 2y = 2;\end{cases}$ (2)$\begin{cases}3x + 4y = 19, \\ x - y = 4;\end{cases}$
(3)$\begin{cases}2x + 3y = -5, \\ 3x - 2y = 12;\end{cases}$ (4)$\begin{cases}\dfrac{x}{2} + \dfrac{y}{3} = -2, \\ 3x - 4y = 6;\end{cases}$
(5)$\begin{cases}6x - 5y = 27, \\ 5x - 2y = 16;\end{cases}$ (6)$\begin{cases}8x - 7y = 18, \\ 3x + 2y = -21;\end{cases}$
(7)$\begin{cases}4(x - y - 1) = 3(1 - y) - 2, \\ \dfrac{x}{2} + \dfrac{y}{3} = 2;\end{cases}$ (8)$\begin{cases}\dfrac{x - 1}{2} - 2y = 4, \\ 1 - \dfrac{y - x}{3} = 3.\end{cases}$
答案：运算题卡 15 二元一次方程组的解法(3)
(1)$\{\begin{array}{l} x=0,\\ y=-1\end{array} $ (2)$\{\begin{array}{l} x=5,\\ y=1\end{array} $ (3)$\{\begin{array}{l} x=2,\\ y=-3\end{array} $
(4)$\{\begin{array}{l} x=-2,\\ y=-3\end{array} $ (5)$\{\begin{array}{l} x=2,\\ y=-3\end{array} $ (6)$\{\begin{array}{l} x=-3,\\ y=-6\end{array} $
(7)$\{\begin{array}{l} x=2,\\ y=3\end{array} $ (8)$\{\begin{array}{l} x=5,\\ y=-1\end{array} $
(1)$\{\begin{array}{l} x=0,\\ y=-1\end{array} $ (2)$\{\begin{array}{l} x=5,\\ y=1\end{array} $ (3)$\{\begin{array}{l} x=2,\\ y=-3\end{array} $
(4)$\{\begin{array}{l} x=-2,\\ y=-3\end{array} $ (5)$\{\begin{array}{l} x=2,\\ y=-3\end{array} $ (6)$\{\begin{array}{l} x=-3,\\ y=-6\end{array} $
(7)$\{\begin{array}{l} x=2,\\ y=3\end{array} $ (8)$\{\begin{array}{l} x=5,\\ y=-1\end{array} $